81+64=c^2

Solution for 81+64=c^2 equation:

81+64=c^2

We move all terms to the left:

81+64-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+145=0

a = -1; b = 0; c = +145;
Δ = b2-4ac
Δ = 02-4·(-1)·145
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{145}}{2*-1}=\frac{0-2\sqrt{145}}{-2}
=-\frac{2\sqrt{145}}{-2}
=-\frac{\sqrt{145}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{145}}{2*-1}=\frac{0+2\sqrt{145}}{-2}
=\frac{2\sqrt{145}}{-2}
=\frac{\sqrt{145}}{-1}
$